Probability question?

A bunch of 12 flowers has three types of flowers, tulips, daffodils and roses.



4 of the flowers are tulips.

3 of the flowers are daffodils.

5 of the flowers are roses



James takes a flower at random from the bunch.

He does not replace it.

He then takes a second flower at random from the bunch.



Work out the probability that the two flowers will not be the same type?



Please show working.

Probability question?
P(not same type)

= [ 4*(12-4) + 3*(12-3) + 5*(12-5) ] / 12P2

= [ 4*8 + 3*9 + 5*7 ] / 12*11

= [ 32 + 27 + 35 ] / 132

= 94 / 132

= 47 / 66
Reply:have u done probabilitie trees ?
Reply:sorry.. i'm bad too in math! XD